Matematika f(x) = 1x² + 1³ - 1(0)f(1) =>..​

anjaliprosaccoulv – March 07, 2023

f(x) = 1x² + 1³ - 1(0)
f(1) =>..​

f(x) = 1x² + 1³ - 1(0)

f(1) = 1(1^2) + 1^3 - 1(0)

f(1) = 1^1 + 1^3 - 1(0)

f(1) = (1.1) + (1.1.1) - (1.0)

f(1) = 1 + 1 - 0

f(1) = 2 - 0

f(1) = 2

f(x) = 1x² + 1³ - 1(0)

f(1) = 1(1)² + 1 - 0

f(1) = 1(1) + 1 - 0

f(1) = ( 1 × 1 ) + 1 - 0

f(1) = 1 + 1 - 0

f(1) = 2 - 0

f(1) = 2

⃢~ Opung~⃠⃫⃟⃤᳗᳐

[answer.2.content]